Math · Algebra I Stretch · Grade 9

Systems of Equations

One equation asks one question. A system asks two at once: find the values that make both true simultaneously — not one and then the other, but at the same instant.
🔗Two Equations, One Answer
A solution pair like (4, 3) must satisfy every equation in the set, not just one. Graph both lines and the answer looks back at you: the intersection.
2x + 3y = 17 5x − 3y = 11 Solve them TOGETHER: solution: (4, 3) 2(4) + 3(3) = 8 + 9 = 17 ✅ 5(4) − 3(3) = 20 − 9 = 11 ✅ 2468 310−2 y x 2x + 3y = 17 5x − 3y = 11 (4, 3) the one place both lines agree
🛠️Two Methods — Pick by the Shape of the System
Both methods do the same thing: collapse two equations in two unknowns into one equation in one unknown. Then back-substitute for the partner variable.
🧩 SUBSTITUTIONswap a variable for what it equals
y = 2x + 1already isolated —
that’s the invitation
3x + y = 16the other equation
3x + (2x + 1) = 16replace y
5x + 1 = 16 → x = 3one unknown left
y = 2(3) + 1 = 7back-substitute
Solution (3, 7). Check the equation you didn’t use: 3(3) + 7 = 16
💡 Best when a variable is already alone on one side (or has a coefficient of 1, so isolating it costs nothing).
💥 ELIMINATIONstack them so a variable cancels
2x + 3y = 17+3y
5x − 3y = 11−3y — already opposites!
7x       = 28ADD the two equations
x = 4divide by 7
2(4) + 3y = 17 → y = 3back-substitute
Solution (4, 3). Check the other: 5(4) − 3(3) = 20 − 9 = 11
💡 Best when coefficients already match or are opposites. If they don’t, scale first: for x + 3y = 14 and 2x − y = 7, multiply the first by −2 to get −2x − 6y = −28, then add → −7y = −21 → y = 3, x = 5.
Always check in BOTH original equations. A pair that satisfies only one of them isn’t a solution to the system — it’s just a point on one line. Substituting into the equation you didn’t use for the last step is the cheapest error-catcher in the lesson.
🎣Three Things a System Can Do
Two straight lines that aren’t parallel cross exactly once — never twice. That geometric fact is why a linear system can never have exactly two solutions.
ONE SOLUTION lines cross once (4, 3) CONSISTENT & independent NO SOLUTION parallel — they never meet 0 = 7  (false) INCONSISTENT solution set is empty INFINITELY MANY the same line, twice −2 = −2  (true) CONSISTENT & dependent
🔍When every variable cancels, don’t panic — read the sentence. A false numeric statement (0 = 7, 1 = 5) means the lines are parallel: no solution. A true one (−2 = −2, 0 = 0) means both equations describe the very same line: infinitely many solutions. The algebra is telling you what kind of system you have.
📱The Crossing Point Is the Whole Point
This is the machinery behind the questions adults actually argue about: which plan is cheaper, how much of each ingredient, and when a business finally breaks even.
📱 Which phone plan is cheaper? 0246810 gigabytes used (x) $0$20$40$60$80 A B (5 GB, $50) — a tie 25 + 5(5) = 50 = 40 + 2(5) ✅ ← under 5 GB: A is cheaper over 5 GB: B is cheaper → A: y = 25 + 5x B: y = 40 + 2x The advice itself flips at the crossing point — that is what a solution to a system means.
🥜Mixture problems are two equations: one for AMOUNT, one for VALUE. Trail mix uses peanuts at $4/lb and cashews at $10/lb; you want 15 lb worth $90.  x + y = 15 (pounds) and 4x + 10y = 90 (dollars). Substituting x = 15 − y gives 60 + 6y = 90 → y = 5, x = 10. Check: 10 lb + 5 lb = 15 lb, and $40 + $50 = $90 ✅
🧪A pharmacist runs the same system. With 20% and 50% saline on the shelf and a need for 12 L at 30%: x + y = 12 (volume) and 0.20x + 0.50y = 3.6 (salt). Answer: 8 L weak + 4 L strong — check 0.20(8) + 0.50(4) = 1.6 + 2.0 = 3.6 ✅. That’s a dosing decision, so the arithmetic has to be exactly right.
📡Your phone solves a system every time it finds you. Each GPS satellite signal gives one equation, and the receiver has four unknowns: latitude, longitude, altitude, and the tiny error in its own clock. Four unknowns need four equations — which is exactly why a phone needs signals from at least four satellites before the blue dot appears.
🔑Key Terms
🔗System of EquationsTwo or more equations sharing the same variables, solved together as one problem. A solution must satisfy every equation in the set.
⏱️SimultaneousAt the same time. British textbooks call these “simultaneous equations” — the solution has to make all of them true at once.
📍Solution PairThe ordered pair (x, y) satisfying both equations. Verify by substituting back into each original.
✖️IntersectionWhere two graphs cross — the geometric picture of the solution.
🧩SubstitutionIsolate one variable, then replace it in the other equation. Two unknowns collapse into one.
💥EliminationAdd or subtract the equations (scaling first if needed) so one variable’s terms cancel to zero.
✕️CoefficientThe number multiplying a variable. Elimination works by engineering coefficients that are opposites.
⚖️Equivalent EquationProduced by multiplying both sides by the same nonzero number, or adding two true equations. Looks different, exact same solutions.
Consistent SystemHas at least one solution — either one crossing point, or infinitely many if the lines coincide.
🚫Inconsistent SystemNo solution. The lines are parallel, and the algebra gives itself away with a false statement like 1 = 5.
📌Remember This
1A solution must satisfy every equation at the same time — that is the whole meaning of simultaneous. Graphically it is the intersection: a single ordered pair, not a range.
2Choose the method by the shape of the system. Substitution when a variable is already alone; elimination when adding or subtracting makes a variable vanish — scaling one or both equations first if the coefficients don’t already match.
3Watch what the algebra says when the variables disappear. 0 = 7 → no solution (parallel). −2 = −2 → infinitely many (same line).
📜Elimination is about 2,000 years old. The Chinese classic Jiuzhang Suanshu (Nine Chapters on the Mathematical Art) has a chapter called fangcheng that solves systems by arranging coefficients in columns and cancelling them — essentially the modern algorithm, roughly 1,800 years before Gauss’s name got attached to it. Scaled up, it becomes Gaussian elimination, and a modern weather model solves systems with millions of simultaneous equations every few hours.
🤔 Think about it
Plan A costs $25 plus $5 per gigabyte; Plan B costs $40 plus $2 per gigabyte, and they cross at exactly 5 GB. Why does the advice flip at that point — and how would you explain to a friend, without doing any algebra in front of them, why the cheaper plan depends entirely on which side of 5 GB they live on?
Two straight lines that aren’t parallel cross exactly once — never twice. Why does that guarantee a consistent linear system can never have exactly two solutions? What would have to change about the equations for two solutions to become possible?
Remember: a system is a question about agreement. Solve for one variable, back-substitute for its partner, then prove the pair works in both original equations — and if the variables all vanish, read the sentence they left behind.
✏️ ClickClass Stretch Anchor Chart · Algebra I · Systems of Equations
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